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# Quantitative Aptitude Questions and Answers

Quantitative Aptitude Questions and Answers contains concepts and test papers on many topics such as average, numbers, compound interests, partnership, problem on ages, calendar, boats and streams, clock, height and distance, percentage, pipes and cisterns, profit and loss, speed, time and distance, simple interest, problem on trains, time and work, etc.

The Aptitude Questions and Answers are very helpful for competitive exams like SSC, CAT (Common Aptitude Test), MAT, GMAT, GRE, UGC, UPSC Exams, ICET, Bank PO, Defence Exams, Bank Exams, Railway Exams and placements like TCS, Wipro, Capgemini, Accenture, Infosys, IBM, Cognizant, Adobe, Cisco, Amazon, Samsung, Google, Yahoo, Facebook, Ola, Paypal, Microsoft, Oracle, etc.

## Table of Contents

## 1) Average Aptitude

1) What is the average of first five multiples of 12?

- 36
- 38
- 40
- 42

The correct answer is **A**

**Explanation:**

Average = 12∗(1+2+3+4+5) ∗

= 12 ∗ 15∗

= 12 ∗ 3= 36

## 2) Numbers Aptitude

1) What is the difference in the place value of 5 in the numeral 754853?

- 49500
- 49950
- 45000
- 49940

The Correct answer is (B)

**Answer with explanation:**

The digit 5 has two place values in the numeral, 5 * 10^{5} = 50,000 and 5 * 10^{1} = 50.

∴Required difference = 50000 – 50 = 49950

## 3) Compound interest Aptitude

1) What is the compound interest on Rs. 2500 for 2 years at rate of interest 4% per annum?

- Rs. 180
- Rs. 204
- Rs. 210
- Rs. 220

The Correct answer is (B)

**Explanation:**

Principal (P) = Rs. 2500

Rate of interest(r) = 4%

Time (t) = 2 years

Compound Interest = Amount ? Principal

Amount(A)=P | 1 + | r | ^{t} | ||

100 |

= 2500 | 1 + | 4 | ^{2} | ||

100 |

= 2500 +

C.I. = 2704 ? 2500 = Rs. 204

Compound interest Aptitude Test 1

Compound interest Aptitude Test 2

Compound interest Aptitude Concepts

## 4) Partnership Aptitude

1) Sohan started a business with a capital of Rs. 80000. After 6 months Mohan joined as a partner by investing Rs. 65000. After one year they earned total profit Rs. 20000. What is share of Sohan in the profit?

- Rs. 5222.2
- Rs. 5777.7
- Rs. 6222.2
- Rs. 6777.7

The Correct answer is (B)

**Explanation:**

Sohan’s capital be C1 = 80000

Mohan’s capital be C2 = 65000

Sohan’s time be T1 = 12 months

Mohan’s time be T2 = 6 months

Profit earned = 20000

**Apply formula:**

Therefore, Sohan’s share =

**Solution: 2**

Ratio of their profits=

Therefore, Profit of Sohan: Profit of Mohan = 32:13

Then, Sohan’s share =

Partnership interests Aptitude Concepts

## 5) Problem on ages Aptitude

1) A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

- 38 years
- 40 years
- 43 years
- 45 years

The Correct answer is (D)

**Explanation:**

Let the age of son = X years

∴Age of mother would be =2X

As per question 20 years ago;

10 (X -20) = 2X – 20

10X – 200 = 2X – 20

10X – 2X= – 20 + 200

8X = 180

X== 22.5 years

∴Age of mother = 22.5 * 2 = 45 years

Problem on ages Aptitude Test 1

Problem on ages Aptitude Test 2

Problem on ages Aptitude Test 3

Problem on ages Aptitude Test 4

Problem on ages Aptitude Test 5

Problem on ages Aptitude Concepts

## 6) Calendar Aptitude

1) If January 1, 1996, was Monday, what day of the week was January 1, 1997?

- Thursday
- Wednesday
- Friday
- Sunday

The correct option is (B)

**Explanation:**

The year 1996 is divisible by 4, so it is a leap year with 2 odd days.

As per the question, the first day of the year 1996 was Monday, so the first day of the year 1997 must be two days after Monday. So, it was Wednesday.

## 7) Boats and Streams Aptitude

1) The speed of a boat in still water is 5km/hr. If the speed of the boat against the stream is 3 km/hr, what is the speed of the stream?

- 1.5 km/hr
- 2 km/hr
- 2.5 km/hr
- 1 km/hr

The correct answer is **B**

**Answer with explanation:**

Let the speed of stream = X km/hr

Speed of boat = 5 km/hr

Speed upstream = 3km/hr

**Apply formula:** Speed upstream = speed of boat – speed of stream

∴ 3 = 5 – X

X = 5 – 3 = 2 km/hr

Boats and Streams Aptitude Test 1

Boats and Streams Aptitude Test 2

Boats and Streams Aptitude Concepts

## 8) Clocks Aptitude

1) How many times the hands of a clock coincide in a day?

- 24
- 22
- 23
- 21

The Correct answer is (B)

**Explanation:**

The hands of a clock coincide only once between 11 O’ clock and 1 O’ clock, so in every 12 hours, the hands of a clock will coincide for 11 times.

∴ In a day or 24 hours, the hands of a clock will coincide for 22 (11+11) times.

## 9) Height and Distance Aptitude

1) Two ships are sailing in the sea on the two sides of a lighthouse. The angles of elevation of the top of the lighthouse observed from the ships are 30° and 45° respectively. If the lighthouse is 100m high, find the distance between the two ships.

- 155.80 m
- 157.80 m
- 159. 80 m
- 161.80 m

The Correctoption is(B)

**Answer with explanation:**

Let AB be the height of lighthouse and C and D be the positions of the ships.

AB = 100 meters, ∠ACB = 45°, ∠ADB = 60°

AC = AB (100m)

AC = 100 m

Distance between ships, CD = AC + AD

Height and Distance Aptitude Test 1

Height and Distance Aptitude Test 2

Height and Distance Aptitude Test 3

Height and Distance Aptitude Test 4

Height and Distance Aptitude Concepts

## 10) Percentage Aptitude

1) 40 % of 280 =?

- 112
- 116
- 115
- 120

The Correct answer; option (A)

**Explanation:**

x % of a given number ‘n’ =

x = 40 and n = 280

∴ 40 % of 280 =* 280 = 112

## 11) Pipes and Cisterns Aptitude

1) A pipe can fill a tank in 6 hours and another pipe can empty the tank in 12 hours. If both the pipes are opened at the same time,the tank can be filled in

- 10 hours
- 12 hours
- 14 hours
- 16 hours

Correct answer; option (B)

**Answer with explanation:**

Part of the tank filled in one hour = | 1 |

6 |

Part of the tank emptied in one hour = | 1 |

12 |

Net part of the tank filled in one hour;

= | 1 | — | 1 |

6 | 12 |

= | 2-1 |

12 |

= | 1 |

12 |

1/12 part of the tank can be filled in one hour.

The tank will be filled completely in 12 hours.

**Solution 2:**

Apply formula; = | XY |

Y—X |

X = 6 hours and Y = 12 hours

6*12 | |

12—6 |

=12 hours

Pipes and Cisterns Aptitude Test 1

Pipes and Cisterns Aptitude Test 2

Pipes and Cisterns Aptitude Concepts

## 12) Profit and Loss Aptitude

1) A shopkeeper sold an article for Rs. 2500. If the cost price of the article is 2000, find the profit percent.

- 23%
- 25%
- 27%
- 29%

The Correct answer is (B)

**Answer with explanation:**

C.P. = Rs. 2000

S.P. = Rs. 2500

Profit or Gain = S.P. -C.P.

= 2500 – 2000 = 500

**Apply formula:** Profit % =__Profit__ ∗100

C.P.

=__500__ ∗100 =25 %

2000

Profit and Loss Aptitude Test 1

Profit and Loss Aptitude Test 2

Profit and Loss Aptitude Test 3

Profit and Loss Aptitude Test 4

Profit and Loss Aptitude Test 5

Profit and Loss Aptitude Concepts

## 13) Speed Time and Distance Aptitude

1) A running man crosses a bridge of length 500 meters in 4 minutes. At what speed he is running?

- 8.5 km/s
- 7.5 km/s
- 9.5 km/s
- 6.5 km/s

The correct answer is (B)

**Answer with explanation:**

- Distance = 500 meters
- Time = 4 minutes ⟶ 4 x 60 = 240 seconds

Speed =^{500}⁄_{240}=^{25}⁄_{12}m/s

We need answer in km/hr:

Speed in km/hr=^{25}⁄_{12}*^{18}⁄_{5}=^{90}⁄_{12}⟶^{30}⁄_{4}= 7.5 km/s

Speed Time and Distance Aptitude Test 1

Speed Time and Distance Aptitude Test 2

Speed Time and Distance Aptitude Test 3

Speed Time and Distance Aptitude Test 4

Speed Time and Distance Aptitude Test 5

Speed Time and Distance Aptitude Concepts

## 14) Simple interest Aptitude

1) If Suresh borrows Rs. 36000 from Mahesh at rate of interest 6% S.I, at the end of four years how much interest Suresh has to pay along with principal amount?

- Rs. 12560
- Rs. 12960
- Rs. 13500
- Rs. 14500

The Correct answer is (B)

**Answer with explanation:**

Principal amount = Rs. 36000

Rate of interest = 6

Number of years or time = 6 years

Simple interest Aptitude Test 1

Simple interest Aptitude Test 2

Simple interest Aptitude Concepts

## 15) Problem on Trains Aptitude

1) A train moving at speed of 80 km/hr crosses a pole in 7 seconds. Find the length of the train.

- 150 m
- 165 m
- 175 m
- 170 m

The correct option is (C).

**Answer with explanation:**

Length of the train is equal to the distance covered by train to cross the pole. So, we will find the distance travelled by the train in 7 seconds by applying the following formula:

Distance= Speed x Time

Speed is given in Km/hr so we will convert it into m/s as answers are given in meters.

Speed=90* = 25 m/s

Time = 7 seconds

Distance = 25 * 7= 175 meters

Problem on Trains Aptitude Test 1

Problem on Trains Aptitude Test 2

Problem on Trains Aptitude Test 3

Problem on Trains Aptitude Test 4

Problem on Trains Aptitude Test 5

Problem on Trains Aptitude Concepts

## 16) Time and Work Aptitude

1) Worker A completes a task in 8 days and worker B completes the same task in 10 days. If both A and B work together, in how many days they will complete the task?

- days.
- days.
- days.
- days.

The Correct answer is (B)

**Explanation:**

Worker A completes the task in 8 days. So in one day he will completepart of the task.

So, A’s one day work =

Similarly, B’s one day work =

∴ (A+B)’s one day work =

of the task is completed in one day so both will complete the whole task in^{days}

Time and Work Aptitude Concepts

## 17) Alligation and Mixture Aptitude

1) A 60 liter mixture of milk and water contains 10% water. How much water must be added to make water 20% in the mixture?

- 8 liters
- 7.5 liters
- 7 liters
- 6.5 liters

The Correct answer is (B)

**Answer with explanation:**

The mixture has 10% water, so the milk would be 90% of 60 liters.

Milk = __90__ * 60 = 54 liters

100

∴Water = 60 ? 54 = 6 liters

Let water to be added = x liters

Now, __6+x__ * 100 = 20

60+x

__6+x__ = __1__

60+x 5

30 + 5x = 60+x

30 – 60 = x ? 5x

– 30 = – 4x

x =__30__ =7.5 liters

4

Alligation and Mixture Aptitude Test 2

Alligation and Mixture Aptitude Concepts

## 18) Surds and Indices Aptitude

1) The value of 5^{1/4} x (125)^{0.25} is

- 5
- 5
- 25

**Answer:** C

**Explanation:**

5^{1/4} x (125)^{0.25}

5^{1/4} × (5^{3} )^{1/4}= 5 =5

## 19) HCF and LCM Aptitude

1) What is the HCF of 1095 and 1168?

- 37
- 73
- 43
- 83

**Answer:** B

**Explanation:**

By Division Method

Therefore the HCF is 73

## 20) Area Aptitude

1) What is the area of a triangle with base 5 meters and height 10 meters?

- 20 square meters
- 35 square meters
- 25 square meters
- 40 square meters

**Answer:** C

**Explanation:**

Area of a triangle = ½ * base * height

So, the area = ½* 5 * 10

=25 square meters

## 21) Ratio and Proportion Aptitude

1) A: B: C is in the ratio of 3: 2: 5. How much money will C get out of Rs 1260?

- 252
- 125
- 503
- None of these

**Answer:** D

**Explanation:**

C’s share = [C’s ratio/ sum of ratios] * total amount

C’s share = (5/10) * 1260

C’s share = 630

## 22) Races and Games Aptitude

1) In a kilometer race, A beats B by 40 meters or by 5 seconds. What is the time taken by A over the course?

- 1 minute 57 seconds.
- 2 minutes.
- 1.5 minutes.
- None of these.

**Answer:** B

**Explanation:**

A runs 1km = 1000 m, it means B runs 1000 – 40 = 960 meters

Time is taken by B for 40 meters = 5 seconds

Time is taken by B for 960 meters = × 960=120 seconds

The time in which B covered 960 meters, A has covered 1000 meters.

∴ A’s time over the course = 120 seconds

= 2 minutes

## 23) Probability Aptitude

1) What is the probability of getting an even number when a dice is rolled?

- 1/5
- 1/2
- 1/3
- 1/4

**Answer:** B

**Explanation:**

The sample space when a dice is rolled, S = (1, 2, 3, 4, 5 and 6)

So, n (S) = 6

E is the event of getting an even number.

So, n (E) = 3

So, the probability of getting an even number P (E) =

= = 3/6 = 1/2

## 24) Volume and Surface Area Aptitude

1) The surface area of a cube is 600 cm2. The length of its diagonal is

- cm
- cm
- 10 cm
- 10 cm

**Answer:** C

**Explanation:**

Surface area of cube = 6 a^{2}

600 = 6 a^{2}

a^{2} = 100

a= =10 cm

Diagonal of cube = a = × 10 = 10 cm

Volume and Surface Area Test 1

Volume and Surface Area Test 2

Volume and Surface Area Test 3

Volume and Surface Area Test 4

Volume and Surface Area Test 5

Volume and Surface Area Concepts

## 25) Decimal Fraction Aptitude

1) Find the missing term of the given expression:

18.834 + 818.34 -? = 618.43

- 217.644
- 218.744
- 217.744
- 217.844

**Answer:** B

**Explanation:**

18.834 + 818.34 – ? = 618.43

Or, 18.834 + 818.340 – 618.43 =?

837.174 – 618.430 = 218.744

Aptitude Decimal Fraction Test Paper 1

Aptitude Decimal Fraction Test Paper 2

Aptitude Decimal Fraction Test Paper 3

Aptitude Decimal Fraction Test Paper 4

Aptitude Decimal Fraction Test Paper 5

## 26) Simplification Aptitude

1) The value of =?

- 98
- 35
- 350
- None of these.

**Answer:** D

**Explanation:**

Aptitude Simplification Test Paper 1

Aptitude Simplification Test Paper 2

Aptitude Simplification Test Paper 3

## 27) Stocks and Shares Aptitude

1) What is the market price of a 9% share when a person gets 180 by investing Rs. 4000?

- 150
- 200
- 250
- 300

**Answer:** B

**Explanation:**

Let the face value of the share = Rs. 100

Dividend per share = 9

As per the question, an income of Rs. 180 is obtained from an investment of Rs. 4000.

So, an income of Rs. 9 is obtained from an investment of Rs. = (4000/180) * 9 = 200

So, the market price of the share = Rs. 200

Aptitude Stocks and Shares Test Paper 1

Aptitude Stocks and Shares Test Paper 2

Aptitude Stocks and Shares Test Paper 3

Aptitude Stocks and Shares Test Paper 4

## 28) Chain Rule Aptitude

1) If 15 men can reap the crops of a field in 28 days, in how many days will 5 men reap it?

- 50 days
- 60 days
- 84 days
- 9.333 days

**Answer:** C

**Explanation:**

Let 5 men can reap a field in x days

So, put the same quantities on the same side.

Men: Days

Now, Men and Days are inversely proportional to each other. If we increase the number of men fewer days will be required to complete the work.

Inversely proportional means

i.e., 5: 15 = 28: x

Or, x = (28*15)/ 5

Or, x = 84 days

Hence, 5 men can reap a field in 84 days.

Aptitude Chain Rule Test Paper 1

Aptitude Chain Rule Test Paper 2

Aptitude Chain Rule Test Paper 3

## 29) True Discount and Banker’s Discount Aptitude

1) The true discount on a bill of Rs. 2700 is Rs. 200. What is the banker’s discount?

- Rs. 210
- Rs. 212
- Rs. 216
- Rs. 218

**Answer:** C

**Explanation:**

Face value = Rs. 2700

TD = Rs. 200

PW (present worth) = FV (face value) – TD (true discount)

= 2700 ? 200 = Rs. 2500

True discount is the simple interest on the present value for the unexpired time.

Now, simple interest on Rs. 2500 for unexpired time = Rs. 200

The rate of simple interest

Banker’s discount is the simple interest on the face value of the bill for unexpired time, i.e., simple interest on Rs. 2700 for unexpired time or remaining time.

R = 8%

Banker’s discount

Aptitude True Discount and Banker’s Discount Test Paper 1

Aptitude True Discount and Banker’s Discount Test Paper 2

Aptitude True Discount and Banker’s Discount Test Paper 3

True Discount and Banker’s Discount Concepts

## 30) Logarithm Aptitude

1) Find the logarithm of 1/256 to the base 2√2.

- 16
- 13/5
- -16/3
- 12

**Answer:** C

**Explanation:**

Let log_{2√2} [1/256] = x

We know that log_{a} y = x is similar to a^{x} = y

So, we can write it as [1/256] = (2√2) ^{x}

Or, (2√2) ^{x} = [1/2^{8}]

Or, [2^{1} * 2^{1/2}]^{x} = 1/2^{8}

Or, 2^{3x/2} = 2-8

Therefore, 3x/2 = -8

Hence, x = (-8 * 2)/ 3 = -16/3

Aptitude Logarithm Test Paper 1

Aptitude Logarithm Test Paper 2

Aptitude Logarithm Test Paper 3

Aptitude Logarithm Test Paper 4

## 31) Square Roots and Cube Roots Aptitude

1) = 80

- 3.74
- 149.67
- 196
- 225

**Answer:** C

**Explanation:**

= 80

∴ ?=14^{2}= 14 × 14 = 196

Aptitude Square Roots and Cube Roots Test Paper 1

Aptitude Square Roots and Cube Roots Test Paper 2

Aptitude Square Roots and Cube Roots Test Paper 3

Aptitude Square Roots and Cube Roots Test Paper 4

Square Roots and Cube Roots Concepts

## 32) Problems on Numbers Aptitude

1) If 30% of a certain number is 12.6, what is the number?

- 24
- 42
- 23
- 32

**Answer:** B

**Explanation:**

Let the required number be x.

So, according to the question:

Aptitude Problems on Numbers Test Paper 1

Aptitude Problems on Numbers Test Paper 2

Aptitude Problems on Numbers Test Paper 3

Aptitude Problems on Numbers Test Paper 4

## 33) Odd Man Out and Series Aptitude

1) Complete the series 2, 5, 9, 19, 37…….

- 76
- 74
- 75
- None of these.

**Answer:** C

**Explanation:**

The second number is one more than twice the first,

2 x 2 +1 = 5

The third number is one less than twice the second,

5 x 2 -1 = 9

The fourth number is one more than twice the third,

9 x 2 +1 = 19

The fifth number is one less than twice the fourth.

19 x 2 – 1 = 37

Therefore, the sixth number is one more than twice the fifth. So, the missing number:

37 x 2 + 1 = 75.

Aptitude Odd Man Out and Series Test Paper 1

Aptitude Odd Man Out and Series Test Paper 2

Aptitude Odd Man Out and Series Test Paper 3

Odd Man Out and Series Concepts

## 34) Algebraic Expressions Aptitude

1) If x^{2}+= 34,x+is equal to

- 3
- 4
- 5
- None of these

**Answer:** D

**Explanation:**

Adding 2 to the L.H.S and R.H.S of the equation:

x^{2}+2+=34+2[∵(a+b)^{2}=a^{2}+b^{2}+2ab]

(x+)^{2}= 36

(x+)= +6,-6

Aptitude Algebraic Expressions Test Paper 1

Aptitude Algebraic Expressions Test Paper 2

Aptitude Algebraic Expressions Test Paper 3

Aptitude Algebraic Expressions Test Paper 4

Algebraic Expressions Concepts

## 35) Permutation and Combination Aptitude

1) In what ways the letters of the word “RUMOUR” can be arranged?

- 180
- 150
- 200
- 230

**Answer:** D

**Answer with the explanation:**

The word RUMOUR consists of 6 words in which R and U are repeated twice.

Therefore, the required number of permutations =

Or, = 180

Hence, 180 words can be formed by arranging the word RUMOUR.

Permutation and Combination Test Paper 1

Permutation and Combination Test Paper 2

Permutation and Combination Concepts